Original Cin

Last time, I wrote that it’d be very difficult to work through the clock’s logic if I used only 5 output pins. Fortunately, there’s no requirement that says I need to do so — leaving two pins available for input should be sufficient. I can use 1 pin to denote AM/PM, and that leaves 10 pins available.
In general, the fewer pins make up a combination for a particular hour, the easier the logic will be to work through, so I’m starting by assigning every available combination that uses only 1 or 2 pins first (for AM and PM, respectively) then I move on to 2 and 3 pin combinations:
0000000001 1AM/PM
0000000010 2AM/PM
0000000100 3AM/PM
0000001000 4AM/PM
0000010000 5AM/PM
0000100000 6AM/PM
0001000000 7AM/PM
0010000000 8AM/PM
0100000000 9AM/PM
1000000000 10AM/PM
1000000001 11AM/PM
1000000010 12AM/PM